Math, asked by ashishbansal21, 10 months ago

May 10, 1999 was a Monday. Then what was the day on 10–Dec–2001?

Answers

Answered by siddharthghumare
1

MONDAY

May 10, 2001 will be a Thursday (1999 was a non-leap year so add one day and 2000 is a leap year, so add 2 odd days).

May 10, 2001 will be a Thursday (1999 was a non-leap year so add one day and 2000 is a leap year, so add 2 odd days).Now start counting the days from May 10, 2001 to 10–Dec–2001. Complete months in between are June, July, Aug, Sep, Oct, Nov – total days = 30 + 31 + 31 + 30 + 31 + 30 = 183 days. Plus 21 days in May and 10 days in Dec.

May 10, 2001 will be a Thursday (1999 was a non-leap year so add one day and 2000 is a leap year, so add 2 odd days).Now start counting the days from May 10, 2001 to 10–Dec–2001. Complete months in between are June, July, Aug, Sep, Oct, Nov – total days = 30 + 31 + 31 + 30 + 31 + 30 = 183 days. Plus 21 days in May and 10 days in Dec.So total days = 214. Net odd days = 4. So 10–Dec–2001 will be 4 days after Thursday, which is Monday.

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Answered by Pitymys
1

Answer:

MONDAY

Step-by-step explanation:

IT  will be a Thursday

as we know that 1999 was a non-leap year so we add one day and 2000 is a leap year, so add 2 odd days.

on counting from May 10, 2001 to 10–Dec–2001. Complete months in between are June, July, Aug, Sep, Oct, Nov –

so total days = 30 + 31 + 31 + 30 + 31 + 30 = 183 days. + 21 days in May and 10 days in Dec.

So total days = 214. Net odd days = 4.

So 10–Dec–2001 will be 4 days after Thursday, which is Monday.

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