Question

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Answer 1

Answer:

1) Li < N <  F

2) Na < Al < Cl

3) Cl₂ < O₂ < N₂

4) Br > Cl > F

5) Na > K > Cs

Explanation:

1) Li= 1.0      N= 3.0       F=4.0

2) The variation of the elements in the 3rd period is Na < Al < Mg < Si < S < P < Cl < Ar

3) The number of bonds formed by the elements is decided by the number of unpaired electrons of each element. Cl has 1 unpaired electron so it can form 1 covalent bond. O has 2 unpaired electrons so it can form 2 covalent bonds. N has 3 unpaired electrons so it can form 3 covalent bonds.

4) The elements F, Cl, Br belong to group 7/17. The atomic radius increases down the group as the shielding effect increases

5) Na, K  and Cs all belong to group 1. Going down the group, the metallic character of the elements increase

Hope it helps