May i have the solution for this question .
question 18.
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mishrasuhani186:
I have solution but they are not allowing me to write
retry
I think you should do it on a paper and upload it.
please and thank you
Answers
Answered by
3
Image clear nahi haiiii
Tumhare pen marks se real lines nhii dikh rahi hain
plzzz post a clear image
hiiii
tera status ek dm shi h
Answered by
7
in Δ OAB
OA=OB ( RADIUS)
ANGLE OAB= ANGLE OBA.....1
similarly
IN Δ O'AB
angle O'AC= angle O'CA.........2
ANGLE OAB=ANGLE O'AC (vertically opposite angles)...3
from 1 ,2 and 3
angle OBA=angle O'CA....4
OO' is transverse between tangents through B and C
angle OBA = angle O'CA.......from 4
therefore tangents through B and C are parallel ( inverse of alternate interior angle property)
hope this helps you
OA=OB ( RADIUS)
ANGLE OAB= ANGLE OBA.....1
similarly
IN Δ O'AB
angle O'AC= angle O'CA.........2
ANGLE OAB=ANGLE O'AC (vertically opposite angles)...3
from 1 ,2 and 3
angle OBA=angle O'CA....4
OO' is transverse between tangents through B and C
angle OBA = angle O'CA.......from 4
therefore tangents through B and C are parallel ( inverse of alternate interior angle property)
hope this helps you
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