Question

Maya is twice as old as Reena. Five years ago her age was three times Reena's age. Find their present ages.​

Answer 1

Let Reena's age be x yrs

So, Maya's age is 2x yrs

5 yrs ago Reena's age =x-5 yrs

5 yrs ago Maya's age = 2x-5 yrs

ATQ, 5 yrs ago Maya's age = 3(x-5) yrs

Therefore,

3(x-5) = 2x-5

or, 3x -15 =2x-5

or, 3x-3x= 15-5

or, x= 10

Maya's present age = 2×10= 20 yrs

Reena's present age = 10 yrs.

hope it helps..☺️

Answer 2

Step-by-step explanation:

I hope this explanation will help you....