mayank has coins of denominations R5 R1 and 50 paise* respectively with him the ratio of the number of these coins is 2:3:5 the total cash with him is R62 how many coins of each denomination does he have?
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Answered by
28
let he has 2x coins of Rs5
3x coins of Rs1
and 5x coins of 50paise =0.5rs
a/q
5(2x)+1(3x)+0.5(5x)=62
10x+3x+2.5x=62
15.5x=62
x=62/15.5=4
so, he has 2×4=8coins of Rs5.
and 3×4=12coins of Rs1
and 5×4=20coins of 50 paise
3x coins of Rs1
and 5x coins of 50paise =0.5rs
a/q
5(2x)+1(3x)+0.5(5x)=62
10x+3x+2.5x=62
15.5x=62
x=62/15.5=4
so, he has 2×4=8coins of Rs5.
and 3×4=12coins of Rs1
and 5×4=20coins of 50 paise
Answered by
0
R5=8 coins
R1=12 coins
50 paise =20 coins
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