Math, asked by shivamjamra143, 9 months ago

Mayur saves Rs.1,45,000 in 10 years.In each year the first,he saved Rs.1000 more than he did in the preceding year. How much did he save in the first year and the last year?​

Answers

Answered by faithturrell14
3

Answer:

1200

Step-by-step explanation:

Answered by Kartikempire
12

Answer:

The money saved in the first year =  Rs. 10,000

The money saved in the last year =  = Rs.19,000

Step-by-step explanation:

Let the money saved in the preceding year =Rs.x

Let the money saved by him in the second year = Rs(x+1000)

Let he money saved by him in the third  year = Rs(x+2000)

and so on

Let he money saved in the last year = Rs(x+9000)

According to the question:-

x + x +1000 +x +2000... x+9000 = 1,45,000

=> 10x +45000 = 1,45,000

=>  10x = 1,00,000

=> x = 10,000

Hence,

The money saved in the first year = Rs. x = Rs. 10,000

The money saved in the last year = Rs. x+9000 = 10,000+9,000 = Rs.19,000

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