Mayur saves Rs.1,45,000 in 10 years.In each year the first,he saved Rs.1000 more than he did in the preceding year. How much did he save in the first year and the last year?
Answers
Answered by
3
Answer:
1200
Step-by-step explanation:
Answered by
12
Answer:
The money saved in the first year = Rs. 10,000
The money saved in the last year = = Rs.19,000
Step-by-step explanation:
Let the money saved in the preceding year =Rs.x
Let the money saved by him in the second year = Rs(x+1000)
Let he money saved by him in the third year = Rs(x+2000)
and so on
Let he money saved in the last year = Rs(x+9000)
According to the question:-
x + x +1000 +x +2000... x+9000 = 1,45,000
=> 10x +45000 = 1,45,000
=> 10x = 1,00,000
=> x = 10,000
Hence,
The money saved in the first year = Rs. x = Rs. 10,000
The money saved in the last year = Rs. x+9000 = 10,000+9,000 = Rs.19,000
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