Question

mbe
On the occasion of New year's day a sweet stall prepared sweet packets. Num
sweet packets and cost of each packet are given as follows.
Cost of packet (in) 525 50 *75
100 125 150
No of packets 20 36 32
29 22 11
Find the mean, median and mode of the data.​

Answer 1

Answer:

Cost of packet Number of packets Cumulative frequency

25 20 20

50 26 46

75 32 78

100 29 107

125 22 129

150 11 140

To find the mean we will add up total cost of packers, then divide by total number of packets.

So, Mean =

(20+26+32+29+22+11)

(25×20+50×26+75×32+100×29+125×22+150×11)

Mean =

140

(500+1300+2400+2900+2750+1650)

=

140

11500

=82.1428

As we can see that the cost of greatest number of packets is Rs. 75 each, so, the mode will be 75.

As we can see there are 140 packets, arranged in increasing order of their cost. So, the middle one will be

2

(140)

=

2

140

=70

th

packet in the list.

So, the median will be the cost of packet corresponding to cumulative frequency just greater or equal to 70 i.e. 75.

Therefore, median is 75.