Question

Mcc spl
ग्रूप वर एक प्रश्न विचारला आहे त्याचे उत्तर द्या
तुमच्या जवळ 100 रुपय आहेत व तुम्हाला 100 रुपयात 100 वस्तू खरेदी करायच्या आहेत
** एक रुपयाला दहा चिमण्या
** दोन रुपयाला एक पोपट
** पाच रुपयाला एक कोंबडी

**करा खरेदी 100 रूपया मध्ये 100 वस्तू जो कोणी 3 तासा मध्ये उत्तर देईल​

Answer 1

Given:

• Cost of ten sparrows (चिमण्या) = Rs. 1

>> Cost of a sparrow = Rs. 1/10

• Cost of a parrot (पोपट) = Rs. 2
• Cost of a hen (कोंबडी) = Rs. 5

______________________________________

Consideration:

• Number of sparrows = x
• Number of parrots = y
• Number of hens = z

Note - none of x, y, z is zero or not even a fraction. They must be positive integers.

______________________________________

Solution:

Here we form two equations,

• Total quantity: x + y + z = 100
• Total money: x/10 + 2y + 5z = 100

We see that we have two equations with three variables; this creates and impossibility of direct solution.

______________________________________

We have:

y + z = 100 - x ..... (i)

2y + 5z = 100 - x/10 ..... (ii)

(ii) - 2 * (i) >>>

2y + 5z - 2y - 2z = 100 - x/10 - 200 + 2x

or, 3z = 19x/10 - 100

or, z = (19x - 1000)/30

For a positive value of (19x - 1000)/30,

19x - 1000 > 0

or, x > 1000/19

or, x > 52 + 12/19

or, x > 52

You see, there is 30 in denominator; that is why we must such values of x for which in numerator, we will get a multiple of 10.

We take x = 60, 70, 80, 90.

______________________________________

• When x = 60, z = 14/3
• When x = 70, z = 11
• When x = 80, z = 52/3
• When x = 90, z = 71/3

Then x = 70, z = 11, y = 19

______________________________________

Therefore the required values of x, y, z are

• x = 70
• y = 19
• z = 11

______________________________________

Answer:

• Number of sparrows (चिमण्या) = 70
• Number of parrots (पोपट) = 19
• Number of hens (कोंबडी) = 11

______________________________________

Confirmation:

Total quantity = 70 + 19 + 11 = 100

Total money = Rs. 70/10 + 2 (19) + 5 (11)

= Rs. 7 + 38 + 55 = Rs. 100

______________________________________

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