Question

MCO (9 TO 12)
The radius of the circle passing through the point (6,2) and
as its nomal and x + 2y = 4 as its diameter is
(A) 10 (8) 2.5 (C)5./ (D) 4.
​

Answer 1

Normals of circle = Diameter

With the help of given equations we can find the center of circle

x+y=6 -(1)

x+2y=4 -(2)

we use elimination method, then 1st equation becomes 2x+2y=12 by multiply 2

and 2nd remains same x+2y=4

after solving these equations we get x=8 and y=-2

so center point of the circle is (8,-2).

and other point is given from which circle is passing i.e (6,2)

If we find the distance between these two points the we will get the radius of the circle.

Therefore, √ ((x2-x1)^2 + (y2-y1)^2)

√( (8–6)^2 + (-2–2)^2)

√( 2^2 + (-4)^2)

√ 4+16

√ 20 = 2√ 5(Ans)

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