mcq in Consider the diameter of the wire is 2 mm and its resistivity is 1.72x10-6 m. Calculate the length of this wire when its resistance is 5 12..
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Answer:
Explanation:
Given: l=50 cm, ρ=40×10
−6
Ωcm, r=0.1 mm =0.01 cm
The resistance R is given by,
R=
A
ρl
=
π×(0.01)
2
40×10
−6
×50
≈6.37Ω
Now the current through it when a potential difference of 2V is applied across it is:
i=
R
V
=
6.37
2
=0.314 A.
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