Question

MCQs


Q.1 Weakest bond is

(A) ionic bond (B) covalent bond (C) coordinate bond (D) hydrogen bond

Q.2 Which of the following statements is true ?

(A)  and  bonds are weak bonds (B)  bond is stronger than  bond

(C) both the bonds are equally strong (D) all the above are wrong

Q.3 Which of the following is nondirectional orbital ?

(A) sp (B) sp3 (C) dsp2 (D) s

Q.4  orbital will formed by

(A) overlapping of s-s orbitals (B) overlapping of sp-s orbitals

(C) coaxial overlapping of p-p orbitals (D) collateral overlampping of p-p orbitals

Q.5 Which of the following compounds has linear geometry ?

(A) CO2

(B) NO2

(C) SO2

(D) SnCl2

Q.6 Which of the following has an atom having incomplete octet ?

(A) BF3

(B) NH4

+ (C) CCl4

(D) PH3

Q.7 The compound having odd number of electron pairs is

(A) XeF2

(B) NaCl (C) BF3

(D) ClO2

Q.8 Electronic configuration of two elements X and Y are 2, 5 and 2, 7, respectively. If these elements

form a covalent compound with each other, then the formula of the compound will be

(A) XY3

(B) X2Y3

(C) XY2

(D) XY

Q.9 What is the oxidation number of carbon in diamond ?

(A) 0 (B) 4 (C) 1 (D) 2

Q.10 The s character in sp3d hybrid orbital will be

(A) 5

1

(B) 4

1

(C) 2

1

(D) 4

3

Q.11 Which of the following is present in the lead pencil ?

(A) Pb (B) Charcoal (C) Graphite (D) Fe

Q.12 What is the type of hybridisation and nature of Ni in [Ni(CN)4

–2 ion ?

(A) dsp2

and diamagnetic (B) sp3d and paramagnetic

(C) dsp3

and diamagnetic (D) sp3

and paramagnetic

Q.13 Which of the following species as boron in sp3

hybridisation state ?

(A) BF4

– (B) BH3

(C) B2H6

(D) BCl3

Q.14 Hydrolysis of SiCl4

occurs very fast, because -

(A) Si is an electrophile due to vacant orbital in it (B) SiCl4

is ionic

(C) SiCl4

is covalent (D) Si is an element of V A group

Q.15 The factor responsible for insolubility of BaSO4

in water is

(A) high dissociation energy (B) high covalent character

(C) high hydration energy (D) high lattice energy​

Answer 1

Answer:

1c

2d

3d

4b

5a

6a

7a

8c

9b

10c

11c

13d

14d

15b

Explanation:

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