Question

me ayudan con esta ecuación diferencial
y'''= - cosx

Answer 1

Step-by-step explanation:

Motion without a specified direction is called a scalar quantity. Vectors are designated by arrows, with the length indicating the relative magnitude of the motion. The distance an object moves is a scalar quanity. The straight-line distance in a specific dierction is the dispalcement vector.

Answer 2

$= \: \: \sf{(15xy – 6x) + (5y – 2)}$

$\:$

$= \: \: \sf{3x(5y – 2) + (5y – 2)}$

$\:$

$\sf{= \: \: (5y – 2)(3x + 1)}$

$\:$