Question

Me poul buy two watches for rupees 574. If he sold one watch at 25% profit and suffered a loss of 20% other. If the selling price of both watch is equal, find the cost price of each watch?

Answer 1

Given

• Mr paul bought 2 watches for 574 rupees
• He suffered 20 % loss and 25 % gain on each watch .
• SP of both watches is same .

To find

• CP of both watches .

Solution

Lets assume that cost price of both watches is x and [574-x ]

$\boxed{\sf{SP = \frac{100 \pm loss/profit}{100} \times CP}}$

USING THE ABOVE MENTIONED FORMULA

$\sf{\implies \frac{100+25}{100} \times [576 - x] = \frac{100-80}{100} \times [x]}$

$\sf{\implies \frac{125}{100} \times [574-x ]= \frac{80}{100} \times [x] }$

$\sf{\implies 80 x = 125[574 -x]}$

$\sf{\implies 80x= 71750 - 125x }$

$\sf{\implies 125 = 80 x = 71750}$

$\sf{\implies 205x = 71750}$

$\sf{\implies x = \frac{71750}{205} \implies x = 350 }$

574 - x = 574 - 350

$\sf{\implies 224 }$

So the cost price of two watches is 350 and 224 rupees

Answer 2

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$\huge\tt{PROBLEM:}$

• Mr poul buy two watches for rupees 574.
• If he sold one watch at 25% profit and suffered a loss of 20% other.
• If the selling price of both watch is equal,
• find the cost price of each watch?

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$\huge\tt{SOLUTION:}$

FORMULA OF SP = 100 +/- profit/loss ÷ 100 × CP

Putting the values given,

↪{100+25/100} × [574-x] = {100 - 80/ 100} × [x]

↪{125/100} × [574 - x] = {80/100} × [x]

↪80x = 125[574 - x]

↪80x = 71750 - 125x

↪80x + 125x = 71750

↪205x = 71750

↪x = 71750/205

↪x = ₹350

Then,

↪574 - x

↪574 - 350

↪₹224

The Cost Prices of the Watches are ₹350 and ₹224 respectively.

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