Mean age of 25 members of a club was 38 years if 15 members with mean age of 45 years have left the club what is the present mean age of the club members
Answers
Step-by-step explanation:
Mean age of 25 members was 38 years.
∴n=25
x
ˉ
=38
x
ˉ
=
n
∑x
∑x=
x
ˉ
×n=25×38=950
Sum of all 25 members age is 950 years.
Now, 5 members with mean 42 years leave, then
n=5
y
ˉ
=42
x
ˉ
=
n
∑y
∑y=
y
ˉ
×n=42×5=210 years.
So, sum of age of remaining 20 members are, 950−210=740 years.
∴ ∑z=740
n=20
New mean,
z
ˉ
=
n
∑z
=
20
740
=37 years
Answer:
Original members:
Mean age of 25 members = 38 years old (Given)
Total age of the 25 members = 25 x 38 = 950 years old
.
Members that left:
Mean age of 5 members that left = 45 years old (Given)
Total age of the 5 members = 45 x 5 = 225 years
.
Present members:
Total number of members at present = 25 - 5 = 20
Total age of the 20 members = 950 - 255 = 695 years old
Mean age of the 20 members =695 ÷ 20 = 34.75 years
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