Mean of 10 numbers was found to be 40 later it was detected that number 45 was misread as 15 find the correct mean
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mean= [(sum of all no.) / (total no.)]
let sum of all numbers= x1+x2.....+x9+15
putting in formula we get,
40= [(x1+x2.....+x9+15) / 10]
from this we get,
(x1+x2.....+x9+15) = 400
x1+x2.....+x9 = 400-15
x1+x2......+x9 = 385_______(1)
now according to question,
45 was misread as 15 so. using formula for mean we get,
new mean=[(x1+x2.....+x9+45) / 10]
new mean = [(385+45) / 10]
new mean = 430/10
new mean = 43
hope this helps you
let sum of all numbers= x1+x2.....+x9+15
putting in formula we get,
40= [(x1+x2.....+x9+15) / 10]
from this we get,
(x1+x2.....+x9+15) = 400
x1+x2.....+x9 = 400-15
x1+x2......+x9 = 385_______(1)
now according to question,
45 was misread as 15 so. using formula for mean we get,
new mean=[(x1+x2.....+x9+45) / 10]
new mean = [(385+45) / 10]
new mean = 430/10
new mean = 43
hope this helps you
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