Question

Mean of 1st n natural numbers is

Answer 1

Step-by-step explanation:

Sum of first "n" natural numbers is given by

$\frac{n(n + 1)}{2}$

mean of these "n" Natural numbers will be

$\frac{n(n + 1)}{2} \div n = \frac{n + 1}{2}$

I HOPE IT WILL HELPFUL TO YOU

Answer 2

$\huge{\boxed{\boxed{\mathfrak{\underline{\overline{\red{S{\green{o{\orange{l{\blue{u{\pink{t{\purple{i{\color{silver}o{\color{cyan}n}}}}}}}}}}}}}}}}}}}$

We know that sum of first n natural numbers is $\frac{n(n+1)}{2}$

So mean of the first n natural numbers =

$\frac{sum \: of \: n \: natural \: numbers}{number} = \frac{\frac{n(n+1)}{2}}{n}$

$= \frac{ \cancel{n}(n+1)}{2} \times \frac{1}{ \cancel{n}} = \frac{n+1}{2}$