Question

Mean of 2,4,12,16,5,9 is x and median of 4,3,x,x-1,12,16 is y. Find x and y.

Answer 1

Answer:

given observations are 2,4,12,16,5,9

mean is x

x=2+4+12+16+5+9÷6

x=48÷6

x=8

the value of x is 8

then other observations will be

4,3,8,7,12,16

Answer 2

The value of x is 8 and y is 8.5

Step-by-step explanation:

Data : 2,4,12,16,5,9

We are given that the mean is x

So,$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}$

$x=\frac{2+4+12+16+5+9}{6}$

$x=8$

We are given that median of 4,3,x,x-1,12,16 is y.

data : 4,3,x,x-1,12,16

data:4,3,8,8-1,12,16

data:4,3,8,9,12,16

Arrange the data is ascending order

Data : 3,4,8,9,12,16

$Median = \frac{\frac{n}{2}+(\frac{n}{2}+1)}{2}\\y = \frac{\frac{6}{2}\text{th term}+(\frac{6}{2}+1)\text{th term}}{2}\\y = \frac{(3+4)\text{th term}}{2}\\y = \frac{8+9}{2}\\y=8.5$

Hence The value of x is 8 and y is 8.5

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