mean of A B and C is equal to 16 find the mean of 3A - 1, 3 b - 1 and 3 C - 1
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Step-by-step explanation:
A+B+C/3=16
A+B+C=16×3
3(A+B+C)=16×3×3
3A+3B+3C-3=144-3
3A-1+3B-1+3C-1=141
(3A-1+3B-1+3C-1)/3=141/3
answer is 47
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