Question

Mean of a,b,c is 16 then find mean of 3a-1,3b-1,3c-1

Answer 1

Answer: 47

Step-by-step explanation:

Given (a+b+c)/3 =16

        (a+b+c)=48

then (3a-1)+(3b-1)+(3c-1)/3

    = [3(a+b+c) - 3] / 3

    = (a+b+c) - 1

    = 48-1

    = 47