mean of the numbers 71, 78 , 75 , 80 , a , b is 80 . If a-b=10 , then find a and b
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Answered by
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Answer:
80 = (71+78+75+80+a+b) / 6
Now, a-b=10
So, a=b+10
Hence, 80 = (71+78+75+80+b+10+b) / 6
480 = 314 + 2b
2b = 480-314
2b = 166
b = 83
Hence, a-b=10
a-83=10
a = 10+83 = 93
Ans, a=93, b=83
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1
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