Math, asked by soni1119, 1 year ago

mean of weight of 50 students In a class is 40 Kg if the weight of teacher is added mean is increased by 500 find the weight of the teacher​


pratyush4211: it is 500 or 50 kg
modernwarfare: 50 kg because the mean weight is increase by 500g
Mohammedahad527: 50kg

Answers

Answered by pratyush4211
33
\underline{\textbf{\huge{Question}}}

mean of weight of 50 students In a class is 40 Kg if the weight of teacher is added mean is increased by 500 g find the weight of the teacher​?

\underline{\textbf{\huge{Answer}}}

Mean Of 50 Students Weight=50

Let Actual Student Weight=x-1,x2,x3,x4,.......x50

We know

\boxed{\mathtt{Average=\frac{Sum\:of\:all\:terms}{Total\:Terms}}}

MEANS

\boxed{\mathtt{\frac{x_1+x_2+x_3....<br /><br />+x_{50}}{50}=40}}

\boxed{\mathtt{x_1+x_2+x_3....<br /><br />+x_{50}=40\times50}}

\boxed{\mathtt{x_1+x_2+x_3....<br /><br />+x_{50}=2000}}

MEANS Actual Weight Of All Students=2000kg

Now Teacher Is Added

Let Teacher Weight=x51

Total Persons Now=51

Mean Increase by 500 g

Now Mean=40.5 kg

\boxed{\mathtt{\frac{x_1+x_2+x_3....<br /><br />+x_{51}}{51}=40.5}}

We know x1...x50=2000

\boxed{\mathtt{\frac{2000+<br /><br />x_{51}}{51}=40.5}}

\boxed{\mathtt{2000+x_{51}=40.5\times\:51}}

\boxed{\mathtt{2000+x_{51}=2065.5\:kg}}

\boxed{\mathtt{+x_{51}=2065.5-2000\:kg}}
=65.5

\boxed{\mathtt{\huge{Teacher=65.5 kg}}}
Answered by ShuchiRecites
32

Error correction : "The mean increased by 500 grams."

Since, Mean = (1/n) ∑

Where, ∑ = x₁ + x₂ +......+ xₙ

Here, Mean = 40 kg and n = 50 students

So, 40 =  ∑ / 50

⇒ 2000 = ∑

When teacher weight is added then mean is increased by 500 g or 0.5 kg.

Let's teacher weight be xₐ.

New Mean = Initial Mean + 0.5 kg = 40 + 0.5

New n = 50 + 1 = 51

New sigma = Initial sigma + xₐ

40 + 0.5 = ( ∑ + xₐ ) / 51

40.5 = ( 2000 + xₐ ) / 51

40.5 × 51 = 2000 + xₐ

2,065.5 − 2,000 = xₐ

65.5 kg = xₐ

⇒Answer : 65.5 kg


sam3255: 65.5 kg
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