mean of X1,X2 is 6 AND MEAN OF X1,X2,X3 IS 7 .THE VALUE OF X3 IS ----
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Answered by
7
(x1+x2)/2 =6
(x1+x2) =6*2
(x1+x2)=12
(x1+x2+x3)/3 =7
x1+x2+x3 =7*3
x1+x2+x3 =21
we know that value of x1+x2,
(x1+x2)+x3 =21
12+x3 =21
ie, x3 = 21-12 =9//
therefore the value of x3 is 9.
(x1+x2) =6*2
(x1+x2)=12
(x1+x2+x3)/3 =7
x1+x2+x3 =7*3
x1+x2+x3 =21
we know that value of x1+x2,
(x1+x2)+x3 =21
12+x3 =21
ie, x3 = 21-12 =9//
therefore the value of x3 is 9.
Answered by
2
Answer is 9 you can solve it very easily if u know the formula of mean .PLZ STUDY HARD as ur xams might be starting in march nd u still not clear with the concept of mean ,median and mode
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