Measure(in degrees) of two complimentary angle are 2 consecutive even integers. Find the angles
Answers
Answered by
12
Hey there!
Let the first integer be x
Then second integer = x+2
A/q,
x+ x+2 = 90
⇒ 2x = 90-2
⇒ x = 88/2
∴ x = 44
So, the two angles are
x = 44
and x+2 = 44+2 = 46
Let the first integer be x
Then second integer = x+2
A/q,
x+ x+2 = 90
⇒ 2x = 90-2
⇒ x = 88/2
∴ x = 44
So, the two angles are
x = 44
and x+2 = 44+2 = 46
Answered by
12
let the first angle be x
and another angle be x +2 ( since it is even consecutive)
now sum ofcomplimentary angles is 90
so x +x+2 =90
2x+2 =90
2x=90-2
2x=88
x=88÷2
x=44
x+2 =46
and another angle be x +2 ( since it is even consecutive)
now sum ofcomplimentary angles is 90
so x +x+2 =90
2x+2 =90
2x=90-2
2x=88
x=88÷2
x=44
x+2 =46
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