Math, asked by Anirudh0757, 8 months ago

Measure of 1 angle.of a parallellogram is 80⁰.What are the measures of the remaining angles?​

Answers

Answered by ashuto56
1

Answer:

120,80,120 answer........

Answered by Anonymous
2

Step-by-step explanation:

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementary

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogram

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*2x = 360* - 160*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*2x = 360* - 160*x = 200*/2 = 100*

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*2x = 360* - 160*x = 200*/2 = 100*The angles of parallelogram are 100,80,100,80

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*2x = 360* - 160*x = 200*/2 = 100*The angles of parallelogram are 100,80,100,80Hope you understand.

In a parallelogram opposite angles are equal and opposite sides are parallel. thus two angles on the same side are supplementarytherefore, in the parallelogramthe angle opposite to the 80* will be 80*and the other two angles will be2x + 2(80*) = 360*2x = 360* - 160*x = 200*/2 = 100*The angles of parallelogram are 100,80,100,80Hope you understand.Plz mark me brainliest

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