Question

measure of one angle of a parallelogram is 40 degree more than the other find the angle​

Answer 1

let the angle be x

so another angle be x - 40

sum of 4 angles are 360

sum of two angles 180

x + x - 40 =180

2x = 220

×= 110
four angles are
110 ,70,110,70
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Answer 2

A- Let ABCD be a parallelogram.

<A=<C ( vertically opposite)

<A=40° (given ) so <C will also be 40°

The sum of the interior angles of a quadrilateral ( given parallelogram )is 360°.

=<A+<B+<C+<D=360°

=40°+<B+40°+<D=360°

=<B+<C = 360° - 80°= 280°

=<B+<C = 280/2 = 140°

Hence , <A = 40°

<B=140°

<C = 40°

<D =140°

The above explanation before my answer is also correct. If you find mistake or difficulty in understanding my answer please comment down .