Question

Measure of two quantities along with the precision of respective measuring instrument is A=2.5ms- +_0.5ms-B=0.10s+_10.01s
value of AB will be?​

Answer 1

Explanation:

ANSWER

Here, A=2.5ms

−1

±0.5ms

−1

, B=0.10s±0.01s

AB=(2.5ms

−1

)(0.10s)=0.25m

AB

ΔAB

=(

A

ΔA

+

B

ΔB

)=(

2.5

0.5

+

0.10

0.01

)=0.3

ΔAB=0.3×0.25m=0.075m=0.08m

(Rounded off to two significant figures)

The value of AB (0.25±0.8)m