Math, asked by amaanvalsangkar, 4 months ago

Measures of opposite angles of a parallelogram
are (3x+20) and (60-x).Find the measure
of its each angles​

Answers

Answered by smrofficial04
0

Answer:

∠PSR = ∠PQR = 50°

∠SRQ = ∠SPQ = 130°

Step-by-step explanation:

Let the parallelogram be PQRS

Opposite angles of a parallelogram are equal.

∠PSR = ∠PQR= 3x + 20 = 60 - x

3x + x = 60 - 20

4x = 40

x = 10

∠PSR = 3x + 20 = 50°

∠PQR = 60 - x = 50°

Adjacent angles are supplementary

∴∠SPQ = 180 - ∠PSR = 180 - 50 = 130°

∠SRQ = ∠SPQ = 130° (opposite angles are equal)

∠PSR = ∠PQR = 50°

∠SRQ = ∠SPQ = 130°

MARK AS BRAINLIEST :)

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