Question

Measures of opposite angles of llgm are (60-x)° and ( 3x-4)° .value of x​

Answer 1

we know that opposite angle of parallelogram are equal

so

60-x=3x-4

-x-3x=-4-60

-4x=-64

x=16

x=16

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Answer 2

Given:

• Measures of opposite angles of llgm are (60-x)° and ( 3x-4)°.

To Find:

• the value of x here

Solution:

★we know that the measure of opposite angles in a parallelogram are equal ★

that means:

$: \tt\longrightarrow (60 - x) \degree = (3x - 4) \degree \\ \\ \\ \\ : \tt\longrightarrow 60 - x \degree = 3x - 4 \degree \: \: \: \: \: \: \: \\ \\ \\ \\ : \tt\longrightarrow 60 + 4 \degree= 3x + x \degree \: \: \: \: \: \: \: \\ \\ \\ \\ : \tt\longrightarrow 64 \degree = 4x \degree \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\ : \tt\longrightarrow x \degree = \cancel \frac{64}{4} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \\ : \tt\longrightarrow x \degree = 16 \degree \bigstar\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\blue{ \underline{ \boxed{ \pink{ \mathfrak{ \therefore \:the \: value \: of \: x = 16 \degree}}}}}$

verification:

let's put 16 in the place of x and check weather it satisfies the rule.

$: \implies \bf60 - x = 3x - 4 \: \: \: \: \: \: \: \\ \\ : \implies \bf60 - 16 = 3(16) - 4 \\ \\ : \implies \bf44 = 48 - 4 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ : \implies \bf44 = 44 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$\sf\huge \blue{hence \: proved \dag}$