Question

Measures of triangle are in ap its perimeter is 30 the difference between longest side and shortest side is 4,then find the measures

Answer 1

Answer:

longest side = 14

shortest side=6

Step-by-step explanation:

Let ,

shortest side/First side of triangle = a,

2nd side of triangle = a+d, (since length of side are in AP)

longest side/3rd side of Triangle = a+2d

where, d=difference in AP

Here

Given, d = 4

therefore we know that,

Perimeter of triangle= sum of all side

30 = a+a+d+a+2d

30 = 3a + 3d

30 = 3a + 12 ( Since d=4)

30-12 = 3a

6 = a ( shortest length/ First side of Triangle)

longest/3rd Side of triangle= 14