Question

Measures of two angles of a triangle are the same and the third angle is 80ᵒ. Find the measure of each angles.
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Answer 1

Answer:

50,50

Step-by-step explanation:

it is an isosceles triangle

in an isosceles triangle 2 sides are equal

SO,

x+x+80=180

2x=180-80

x=100/2

 =50

so both sides are 50 and 50

checking

50+50+80=180 degrees

in a triangle sum of three angles is 180 degrees

                                   

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Answer 2

Given :

• Measures of two angles of a triangle are the same and the third angle is 80ᵒ.

To Find :

• Measure of each angle of the Triangle.

Solution :

$\longmapsto\tt{Let\:the\:same\:angle\:be=x}$

As we know that Sum of all angles of a Triangle is 180°. So ,

$\longmapsto\tt{x+x+80^{\circ}=180^{\circ}}$

$\longmapsto\tt{2x+80^{\circ}=180^{\circ}}$

$\longmapsto\tt{2x=180^{\circ}-80^{\circ}}$

$\longmapsto\tt{2x=100^{\circ}}$

$\longmapsto\tt{x=\cancel\dfrac{100}{2}}$

$\longmapsto\tt\bf{x=50^{\circ}}$

So , The Measure of two same angles is 50° .

VERIFICATION :

$\longmapsto\tt{x+x+80^{\circ}=180^{\circ}}$

$\longmapsto\tt{50+50+80^{\circ}=180^{\circ}}$

$\longmapsto\tt{100^{\circ}+80^{\circ}=180^{\circ}}$

$\longmapsto\tt\bf{180^{\circ}=180^{\circ}}$