Question

Measures of two angles of a triangle are the same and the third angle is 80ᵒ. Find the measure of each angle.​

Answer 1

Answer:

as we know the sum of the angles of triangle=180 . here has given that one angle = 80 .

so, let consider both angles x and x

x+x+80=180

2x+80=180

2x=180-80

2x=100

x=100/2

x=50

therefore the angles of triangle are 80,50,50

as we know the sum of the angles of triangle=180

Answer 2

$\huge{ \underline{ \underline \mathfrak \red{Answer}}}$

• The measure of each angle is 50° .

$\sf \large \underline \pink{According \: to \: question}$

It is given that, measures of two angles of a triangle are the same and the third angle is 180°

We have to calculate the measure of each equal angles.

$\tt \underline \purple{let \: the \: each \: equal \: angle \: be \: x°}$

Now, we know that the sum of angles in a triangle is 180° .

$\sf \large \underline \green{by \: putting \: the \: value \: we \: get}$

$\implies x + x + 80 = 180$

$\implies \: 2x + 80 = 180$

$\implies \: 2x = 180 - 80$

$\implies \: 2x = 100$

$\implies \: x = \frac{100}{2}$

$\implies \: x = 50$

• Hence, the measure of each angle will be 50° .