measuring cylinder contains water up to the level 46mL. The water level rises to 74 mL when a solid of mass 56 g is immersed in it. Find the density of solid.
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Answered by
5
Answer:
Initial level of water vi=55 ml
Final level of water vf=83ml
Volume of stone Vstone=Vf−Vi=83−55=28 ml
Answered by
9
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Gɪᴠᴇɴ:
A measuring cylinder contains water up to the level 46mL. The water level rises to 74 mL when a solid of mass 56g is immersed in it.
Tᴏ Fɪɴᴅ:
The density of Solid = ?
Sᴏʟᴜᴛɪᴏɴ:
A.T.Q,
⇢Initial level of water v1 = 46 mL
⇢Final level of water v2 = 74 mL
⇢So,volume of rubber stopper v
= V2 – V1
= 74 – 46
⇢Volume of rubber stopper
v = 28 mL
Nᴏᴡ ,
⇢we have
Density = mass / volume
or, density = 56/28
or, density = 1.6 g/mL
Therefore,
The Density of solid = 1.6 g/mL ✔︎
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