Question

Mechanical energy of a particle P moving on x-axis is given by E=AX^2+BV^2  where x is displacement of  P from x=0 and v is the velocity of P at x. A and B are positive constants. If its mechanical energy is conserved, then:
A) the x-coordinate of the particle can be 
B)the particle is at equilibrium at x=
c)maximum velocity of the particle during its motion is 
D)acceleration of the particle as a function of x is 



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Answer 1

Answer:

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