mechanical power is represented by p=fv+Av^3p where f is the force,v is the velocity A is the area and p is the velocity
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so the given P=FV+AV^3
THE FORMULA FOR F= MLT^-2 (ma)
V=LT^-1 (DISTANCE/TIME)
a= l*b(L^2)
A) THE DIMENSIONAL FORMULA OF POWER IS
FORMULA =FORCE/AREA
SO MLT^-2/L^2 =ML^-1T^-2
here if we want to add two variables say 3x +4x here only if x is the same variable we can add so the dimension of fv must be equal to av^3 suppose if they ask u 2 find the dimension of some constant by giving some equation plz keep ths idea in ur mind
b) p=ML^-1T^-2 in Lhs and in rhs
fv =( MLT^-2) (LT^-1)=ML^T^-3
AV^3= (L^2) (LT^-1)^3=L^5T^-3
so c here acc to the idea i said before only if de dimensions of all the 3 quantities we can say that they are dimensionally crt so here it is not dimensionally valid
Explanation:
cathykate:
the answer is wrong
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