Chemistry, asked by chem111, 1 year ago

mechanism of sharpless epoxidation​

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Answered by priyanka9432
1

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Description: The Sharpless Epoxidation is an enantioselective epoxidation of allylic alcohols.

Mechanism: Without going into specific details, what happens in the Sharpless epoxidation is that the titanium binds to the allylic alcohol, t-butylhydroperoxide, and the tartate in such a way as to provide a chiral environment whereby one face of the alkene is preferentially exposed to the oxidant. The outcome of a Sharpless epoxidation can be predicted by using the following mnemonic. Placing the CH2OH group in the upper right hand quadrant, using (–)-DET will lead to epoxidation of the top face, whereas (+)-DET will lead to epoxidation of the bottom face.

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Answered by byrdjoseph13811
1

Mechanism: Without going into specific details, what happens in the Sharpless epoxidation is that the titanium binds to the allylic alcohol, t-butylhydroperoxide, and the tartate in such a way as to provide a chiral environment whereby one face of the alkene is preferentially exposed to the oxidant.


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