Question

median of the observation 35,48,29,42,27,31​

Answer 1

$Given \: data : 35,48,29,42,27,31$

/* Rearranging the data in ascending order, we get */

$27,29,31,35,42\: and \: 48$

$Number \:of \: terms (n) = 6 \: (even )$

$Median = Average \: of \: \frac{n}{2} \: and$

$\Big( \frac{n}{2} + 1 \Big)^{th} \: terms$

$= Average \: of \: \frac{6}{2} \: and$

$\Big( \frac{6}{2} + 1 \Big)^{th} \: terms$

$= Average \: of \: 3^{rd} \: and \: 4^{th} \:terms$

$= \frac{31+35}{2}$

$= \frac{66}{2}$

$= 33$

Therefore.,

$\red{Median}\green { = 33}$

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