Median of triangle meets a (0,-3) and its two vertices are at (-1, 4) and (5,2) then find the third vertice
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We know that:
if x,y is the median then :
x=(x1+x2+x3)/3
y=(y1+y2+y3)/3
Given:
Let the third vertex be a,b
(a+5-1)/3=0
=a+4=0
=a=-4
Then:
(b+2+4)/3=-3
b+6=-9
=b=-15
The third vertex is(a,b) or (-4,-15)
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