Medians BE and CF of a triangle ABC are equal. Prove that the triangle is isosceles
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Lets take the triangle BCF and triangle EBC
FC = EB
Angle ECB = Angle FBC
BC is the common side
So triangle ECB and triangle FBC are congruent
FB = EC
And AF = AE
SO FB +AF = EC+ AE
AB = AC ( PROVED)
FC = EB
Angle ECB = Angle FBC
BC is the common side
So triangle ECB and triangle FBC are congruent
FB = EC
And AF = AE
SO FB +AF = EC+ AE
AB = AC ( PROVED)
Answered by
13
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