Medians of binomial and poisson distribution
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Answered by
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☆ranshsangwan☆☆
Let
X
X
be a random variable that follows a Poisson distribution with parameter
λ=5
λ=5
, then we have
P(X≤4)≈0.440493
P(X≤4)≈0.440493
and
P(X≤5)≈0.615961
P(X≤5)≈0.615961
. So, it's clearly the median
(
x
50
)
(x50)
of
X
X
is between
4
4
and
5
5
, more precisely
x
50
≈4.32937026824559119408
x50≈4.32937026824559119408
obtained by a computer program. Unfortunately, we are only allowed to use a simple scientific calculator so basically it's difficult to obtain that precise value using a simple scientific calculator by trial and error or Newton method due to time limit. I managed to obtain
x
50
≈4.33
x50≈4.33
by trial and error method, so I answered
4
4
because I rounded to the nearest integer. But some of friends argued and they answered
5
5
because they used the nearest rank method,
x
50
=⌈4.33⌉=5
x50=⌈4.33⌉=5
Let
X
X
be a random variable that follows a Poisson distribution with parameter
λ=5
λ=5
, then we have
P(X≤4)≈0.440493
P(X≤4)≈0.440493
and
P(X≤5)≈0.615961
P(X≤5)≈0.615961
. So, it's clearly the median
(
x
50
)
(x50)
of
X
X
is between
4
4
and
5
5
, more precisely
x
50
≈4.32937026824559119408
x50≈4.32937026824559119408
obtained by a computer program. Unfortunately, we are only allowed to use a simple scientific calculator so basically it's difficult to obtain that precise value using a simple scientific calculator by trial and error or Newton method due to time limit. I managed to obtain
x
50
≈4.33
x50≈4.33
by trial and error method, so I answered
4
4
because I rounded to the nearest integer. But some of friends argued and they answered
5
5
because they used the nearest rank method,
x
50
=⌈4.33⌉=5
x50=⌈4.33⌉=5
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