medians of triangle PQR intersect at O. show that ar(POQ)=1/3 ar(PQR)
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HEY MATE!!!
GIVEN:- IN TRIANGLE PQR and O is the point of intersection of median
To proof ar(POQ) = 1/3 ar( PQR)
solution :- In triangle PQR
PD is the median
ar ( PDQ ) = ar ( PDR) median divides the triangle into two triangle with equal areas
arc ( PDQ ) - ar ( QOR) = ar ( PDR) - ar( QOR) subtracting area of QOR from LHS and RHS
ar ( POQ ) = ar ( POR) ---- 1
RF is the median
ar( PRQ) = ar ( FRQ ) median divides the triangle into two triangle with equal areas
ar( PRQ ) - ar ( POF ) = ar ( FRQ ) - ar ( FOQ)
ar ( POQ ) = ar ( QOR)-----2
From 1 and 2 we get,
ar ( POQ) = ar ( QOR) = ar ( POR) = ar ( PQR)
ar ( POQ) = 1/3 ar (PQR)
diagram is attach
HOPE IT HELPS YOU!!!
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