Question

mee app ko bro bhulaa aya apa bol doo.​

Answer 1

Answer:

Given :

Father is now 3 times as old as his son.

Four years ago he was four times as old as his son.

To Find :

Present Age of his son .

Solution :

\longmapsto\tt{Let\:Present\:age\:of\:his\:son\:be=x}⟼LetPresentageofhissonbe=x

As Given that Father is 3 times as old as his son. So ,

\longmapsto\tt{Father=3x}⟼Father=3x

Before 4 years :

\longmapsto\tt{Age\:of\:son=x-4}⟼Ageofson=x−4

\longmapsto\tt{Age\:of\:father=3x-4}⟼Ageoffather=3x−4

A.T Q :

\longmapsto\tt{3x-4=4(x-4)}⟼3x−4=4(x−4)

\longmapsto\tt{3x-4=4x-16}⟼3x−4=4x−16

\longmapsto\tt{3x-4x=-16+4}⟼3x−4x=−16+4

\longmapsto\tt{-x=-12}⟼−x=−12

\longmapsto\tt\bf{x=12}⟼x=12

So , The Present Age of his son is 12 years .

Option 4) 12 years is Correct .