Question

Meena father age is 6 times Meena age. 5 yrs from now she will be 1 by 3 of her father age. What are their present ages.(by step by step explaination)

Answer 1

AT PRESENT

Let the age of Meena be x years.

Let the age of father of Meena be y years.

Age of Meena's father = 6 * Age of Meena

y = 6 * x

AFTER 5 YEARS,

Age of Meena = (x + 5) years

Age of father of Meena = (y + 5) years

(x + 5) * 3 = (y + 5). ....(1)

PUT y = 6 * x

(x + 5) * 3 = 6 * x + 5

3x + 15 = 6x + 5

3x = 10

x = 10/3

PUT x = 10/3 in equation 1,

(10/3 + 5) * 3 = y + 5

25/3 * 3 = y +5

y = 25 - 5

y = 20

Age of Meena = 10/3 years

Age of father of Meena = 20 years

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given that Meena Father age is 6 times of Meena age
• After 5 years Meena will be 1/3 of her father age .

To Find:

• The present ages of Meena and his Father

Solution:

Let the age of Meena = x years

Age of Father = 6x years

After 5 years

Meena age will be = ( x + 5 ) years

Meena Father Age = ( 6x + 5 ) years

______________________________

According to the Question :

=> Meena age = 1/3( Meena Father Age )

=> ( x + 5 ) = 1/3( 6x + 5 )

=> 3( x + 5 ) = ( 6x + 5 )

=> 3x + 15 = 6x + 5

=> 6x - 3x = 10

=> 3x = 10

=> x = 10/3

______________________________

Present age of Meena ( x ) = 10/3 years

Present age of Meena Father ( 6x )

= 6( 10/3 )

= 20 years

Hence Present of Meena is 10/3 years and of father is 20 years .