Meena has a cumulative deposit amount of ₹ 400 per month at 10% per annum simple interest. If she gets ₹ 26550 at the time of maturity. Find the total time for which the account was held ?
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Answers
Answer:
Let say account was held for n moths
1st Deposit got interest for n months
2nd deposit got for n - 1 months
and last Deposit nth for 1 month
Interest for n months = 400 * (n/12) * 10/100 = 40n/12 = 10n/3
10n/3 , 10(n-1)/3 ...+ 10/3
400n is deposited anount & interest
Sum = 400n + (n/2)(10n/3 + 10/3)
= 400n + 5n²/3 + 5n/3
400n + 5n²/3 + 5n/3 = 30100
=> 5n² + 1200n + 5n = 90300
=> n² + 241n - 18060 = 0
=> n² + 301n - 60n - 18060 = 0
=> (n + 301)(n - 60) =0
=> n = 60
Account was held for 60 months = 5 years
Answer:
Answer:
Meena has a cumulative deposit amount of 400 per month at 10% per annum simple interest. If she gets 26550 at the time of maturity. Find the total time for which the account was held ?
Common factor
5n²+1205n-79650
5(n² +241n 15930)
*Use the sum-product pattern
5(n² +241n 15930)
5(n²+295n-54n - 15930)
★Common factor from the two pairs
5(n²+295n - 54n - 15930)
5(n(n+295) 54(n +295))
★Rewrite in factored form
5(n(n+295) 54(n +295))
5(n54)(n+295)
Step-by-step explanation:
54months 4.5 years
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Step-by-step explanation:
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