Meena has some 50 rupees currencies arranged as per its serial number. The total amount she had was ₹850. If the serial number in the first currency is 105 what is the serial number in the last currency?
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Answer:
Perimeter of a square = 4 × length of its side ... area. • Area of a rectangle = length × breadth ... 1 cm is joined to a square of ... 4 × side of square field = 4 × 80m = 320m.
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Answer:
Let no. of Rs. 50 notes = x
no. of Rs. 100 notes = y
Total notes = 25
⇒ x + y = 25
⇒ x = 25-y
total amount only in Rs. 50 notes = 50x
total amount only in Rs. 100 notes = 100y
Total amount = 2000
⇒ 50x + 100y = 2000
⇒50(25-y) + 100y = 2000
⇒50×25 - 50y + 100y = 2000
⇒1250 +50 y = 2000
⇒ 50y = 2000-1250 = 750
⇒ y = 750/50 = 15
x = 25-15 = 10
No. of Rs. 50 notes = 10
No. of Rs. 100 notes = 15
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