meena is 10 years older than sana five years ago one seventh of meena was equal to one fifth of sana's age find their present ages
Answers
Step-by-step explanation:
Let the present age of Sana be 'a', so hence the present age of Meena should be a + 10, being 10 year more than that of Sana.
5 year ago:
Age of Sana = a - 5
Age of Meena = a + 10 - 5 = a + 5
Also,
= > 1/7 of Meena's age = 1/5 of Sana's age
= > 1/7 of ( a + 5 ) = 1/5 of ( a - 5 )
= > 5( a + 5 ) = 7( a - 5 )
= > 5a + 25 = 7a - 35
= > 35 + 25 = 7a - 5a
= > 60 = 2a
= > 30 = a
Age of Sana = a = 30 year
Age of Meena = a + 10 = 30 + 10 = 40 year
Answer:
Sana = 30 years and Meena = 40 years
Step-by-step explanation:
Let the present age of Sana be x.
Meena is 10 years older than Sana. Therefore, the age of Meena is (x + 10) years.
5 year ago
- Age of Sana = (x - 5) years
- Age of Meena = x + 10 - 5 = (x + 5) years
As per given condition,
→ 1/7 of (x + 5) = 1/5 of (x - 5)
→ 5(x + 5) = 7(x - 5)
→ 5x + 25 = 7x - 35
→ 35 + 25 = 7x - 5x
→ 60 = 2x
→ 30 = x
Hence, the Present age of:
Sana = x = 30 years
Meena = x + 10 = 30 + 10 = 40 years