Question

Meena is three times as old as Leena . after 5 years , she will be as twice as age of Leena , find there present ages​

Answer 1

Answer :-

Let present age of meena = X years

Let present age of meena's mother =Y years

After five years age of meena =(x + 5) years

After five years age of meen's mother =(Y +5) years

According to question

$y = 4x - - - (1)$

$y + 5 = 3(x + 5) - - - (2)$

Put (1) in (2) , we get

$4x + 5 = 3x + 15$

$4x - 3x = 15 - 5$

$x = 10$

$y = 40$

Meena's present age =10 years

Meena's mother's present age =40 years