Meena is x years old while her mother is x^2years old. five years hence her mother will be 3 times as old as Meena. find their present age
Answers
Answer:
Step-by-step explanation:Given : meena present age = x years
His mother Mrs Veena's present age = x² years
After 5 years,
Ashu's age will be = (x + 5) years
His mother Mrs Veena's age will be = (x² + 5) years
A.T.Q
(x² + 5) = 3(x + 5)
(x² + 5) = 3x + 15
x² - 3x -15 + 5
x² - 3x - 10 = 0
x² - 5x + 2x - 10 = 0
[By middle term splitting]
x(x - 5) + 2(x - 5)
(x + 2)(x - 5)
(x + 2) = 0 or (x - 5) = 0
x = -2 or x = 5
Since, x (age) can’t be negative, x ≠ - 2 , so x = 5.
meena present age = x years = 5 years
And His mother Mrs Veena's present age = x² years = 5² = 25 years
Hence, meena's present age is 5 years and His mother Mrs Veena's present age is 25 years.
pls mark it as brainliest
Step-by-step explanation:
The mathematical work is given above.
Concept:
Read the question and at the same time go writing the information. Take their present age as some variable x , then relate both their ages, one is x, other is x^2. Then write what will be their ages 5 years after. Then see whose age will be greater and multiply the smaller term with that number ( in this case it is 3) to make equal terms on both sides of equation. Then solve get the answer.
note: Since we were solving quadratic equation we will get two answers for meena's age. Try to reason out why the negative age doesn't make sense.
It is mathematically correct but as soon as you take meena's age -2 yrs her mother age becomes 4 yrs !!! which seems logically incorrect.
Therefore we neglect it and took the other solution which for meena age is 5 yrs, and mother age is 25 yrs, which makes sense!!!!.
Maths can be funny at same time isn't?
Hope it helps you.
