Question

Meena married 10 years ago. Today her age is 7
5
times her age at the time of her marriage. Her daughter age is 1
5
of her age. What is the ratio of Meena‘s age to her daughter age after 5 years?

Answer 1

The ratio of Meena‘s age to her daughter's age after 5 years is (10 : 3).

Step-by-step explanation:

We are given that Meena married 10 years ago. Today her age is (7 /5)  times her age at the time of her marriage. Her daughter age is (1/5)  of her age.

Let the present age of Meena be x years.

So, according to the question which says today her age is (7 /5)  times her age at the time of her marriage, that means;

                           $x = \frac{7}{5}\times (x-10)$

                           $5x = {7}\times (x-10)$

                           $7x-5x = 70$  

                             $2x=70$

                              $x=\frac{70}{2} = 35$

So, the age of Meena is 35 years.

Now, it is given that her daughter's age is (1/5)  of her age, that means;

Age of daughter =  $\frac{1}{5}\times 35$  = 7 years.

Now, Meena's age after 5 years = 35 + 5 = 40 years

Daughter's age after 5 years = 7 + 5 = 12 years

Hence, the ratio of Meena's age to her daughter age after 5 years = $\frac{40}{12}$

                      =  $\frac{10}{3}$  = 10 : 3.