Meena's father's present age is six times Meena's age. Five years from now she will be one third of her father's present age. What are their present ages?
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let,
meena's age be x
meena's father's age be 6x
Five years from now
meena's age will be 1/3(6x)
meena's father's agr will be 6x+5
A/Q
x+5+6x+5=2x+6x+5
=>x+6x-2x-6x=5-5-5
=> -x =-5
=> x =5
therefore, meena's age = x
= 5
meena's father's age = 6x
= 6×5
= 30
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