Question

meena wants to make a cloth mask by joining two equal size triangular pieces of sides 5cm, 8cm, and 5cm.How much cloth has she required? ​

Answer 1

Answer:

24 cm²

Step-by-step explanation:

Let the sides of the traingular part be a, b and c

a = 5 cm

b = 5 cm

c = 8 cm

s (semi - perimeter) = (a + b + c)/2

=> s = 18 cm/2

=> s = 9 cm

Area of 2 isosceles triangles

= 2√s(s - a)(s - b)(s - c)

{using Heron's Formula which is

√s(s - a)(s - b)(s - c)

so for two it will be

2√s(s - a)(s - b)(s - c)}

= [2√9(9 - 5)(9 - 5)(9 - 8) ] cm²

= [2√(9 * 4 * 4 * 1)] cm²

= (2√144) cm²

= (2 * 12) cm²

= 24 cm²

Hence, Meena would require 24 cm² of cloth to make the mask......

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Answer 2

Given :- meena wants to make a cloth mask by joining two equal size triangular pieces of sides 5cm, 8cm, and 5cm.How much cloth has she required ?

Solution :-

we know that,

• when sides of ∆ are given as a, b and c , than,
• semi - perimeter (s) = (a + b + c)/2 .
• Area of ∆ = √[s * (s - a) * (s - b) * (s - c)]

given that, sides of triangular pieces are 5cm, 8cm and 5cm.

So,

→ s = (5 + 8 + 5) / 2 = 18/2 = 9cm.

Than,

→ Area of one triangular piece = √[9 * (9 - 5) * (9 - 8) * (9 - 5)] = √[9 * 4 * 1 * 4] = √(3² * 4²) = 3 * 4 = 12 cm².

Therefore,

→ Total area of two triangular pieces = 12 * 2 = 24 cm². (Ans.)

Hence, Meens required 24cm² cloth to make cloth mask.

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3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

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